#include <stdio.h>

#include <stdlib.h>

int a,b,c,d,e;

int f,g,h,i,j;

int add1;

int s;

int add2;

int operation1;

int subtraction;

int Remainder;

int checkdigit;

int main()

{

`printf("Enter First Six Digits :-");`

scanf("%d %d %d %d %d %d " , &s , &a , &b, &c , &d , &e);

`printf("Enter Second Five Digits :-");`

`scanf("%d %d %d %d %d" , &f , &g , &h , &i , &j);`

`add1 = s + b + d + f + h + j ;`

`add2 = a + c + e + g + i ;`

`operation1 = ((3*add1) + add2);`

`subtraction = (operation1 - 1);`

`Remainder = subtraction%10 ;`

`checkdigit = (9 - Remainder);`

`printf("Bar code Check digit :- %d " , checkdigit);`

}

So when I try to run this program, my screen only shows the first six digits; when I put the value, I do not get the first five digits message. so where I went wrong I do not get any errors when I try to run this program.your text