Code Snippet

Code:

from collections import Counter

s1 = "yxxx"
s2 = "xyyy"

map1 = Counter(s1)
map2 = Counter(s2)

print(map1.keys())
print(map2.keys())

print("Are map1's keys and map2's keys equal:", map1.keys() == map2.keys())

print()
print(map1.values())
print(map2.values())
print("Are map1's values and map2's values equal:", map1.values() == map2.values())
print("Are SORTED map1's values and map2's values equal:", sorted(map1.values()) == sorted(map2.values()))

Results:

dict_keys(['y', 'x'])
dict_keys(['x', 'y'])
Are map1's keys and map2's keys equal: True

dict_values([1, 3])
dict_values([1, 3])
Are map1's values and map2's values equal: False
Are SORTED map1's values and map2's values equal: True

I understand that the return type of keys() function similar to a set-like view, so when evaluating equality the order wouldn’t matter, but how about values()? Even though the values in map1 and map2 are the same, the value returned is still False. But why does calling sorted() return True although the order of the values remain unchanged?