I am launching an Anconda prompt from a Windows shortcut.
Its target is %windir%System32cmd.exe "/K" %PYTHONDIR%Scriptsactivate.bat root,
with PYTHONDIR=C:UsersUser1Anaconda.

At the prompt I get

(base) C:UsersUser1Documents> jupyter kernelspec list
[ListKernelSpecs] WARNING | Config option `kernel_spec_manager_class` not recognized by `ListKernelSpecs`.
Available kernels:
  python3    C:UsersUser1AppDataRoamingjupyterkernelspython3

(base) C:UsersUser1Documents>

In the corresponding C:UsersUser1AppDataRoamingjupyterkernelspython3kernel.json (#1) I have

{
 "argv": [
  "C:\Users\user1\Documents\appls_mydocs\anaconda3\python.exe",
  "-m",
  "ipykernel_launcher",
  "-f",
  "{connection_file}"
 ],
 "display_name": "Python 3",
 "language": "python"
}

And in another C:UsersUser1Anacondasharejupyterkernelspython3kernel.json (#2) I have

{
 "argv": [
  "C:/Users/User1/Anaconda\python.exe",
  "-m",
  "ipykernel_launcher",
  "-f",
  "{connection_file}"
 ],
 "display_name": "Python 3",
 "language": "python"
}

Where is it stated which kernel.json to use to select the jupyter kernel (in this case, #1)?
I would actually mean to use #2, whenever I launch an Anaconda prompt in that same directory.