I want to create the list [0, 2, 3, …, 234] in python, possibly within a row and without listing all numbers explicitly
I know that following code works:
list1 = [0]
for i in range(2,235):
list1.append(i)
But are there any possibilities to finish that within a row?
1
Another efficient way, combining simplicity and performance, is to use unpacking:
list1 = [0, *range(2, 235)]
1
list1 = [0] + list(range(2,235))
list will expand a lazy enumerator.
This is probably not as efficient as the other two answers but is a direct translation of your code to a 1 liner.
list1 = [0] + [i for i in range(2,235)]