#include<stdio.h> 

int main() 
{ 
    static char *a[] = {  
        "so", "how", "are", "you" 
    }; 
     char *ptr[] = {a+3, a+2, a+1, a}; 
    char ***p = ptr; 
    
    // Output 1
    printf("%sn", **++p); // Outputs the string pointed to by p after incrementing p

    // Output 2
    printf("%sn", *--*++p+3); // This is the statement in question

   

    return 0; 
}

After executing First print p is pointing to ptr[1], so output 1 = “are”.

Current State of p:
After ++p, p points to ptr[2], which is a + 1.

Dereferencing *++p:
Dereferencing p (which is now a + 1) gives us a + 1. This points to the string “how”.

Applying — * ++p:
Decrementing a + 1 results in a. Thus, — * ++p points to a, which is the start of the string “so”.

Dereferencing * — *++p:
Dereferencing a gives us the string “so”.

Pointer Arithmetic * — *++p + 3:
Adding 3 to the pointer to “so” moves the pointer past the end of the string “so”. This points to the null terminator ”.

After My analysis Result:
The pointer points to the null terminator, so the result of * — *++p + 3 is an empty string.

But In compiler the output is coming as “how”(output 2) What mistake I might be doing?