This is the code for my project, with self.keywords being a list containing keywords

escaped_keywords = list(map(re.escape, self.keywords))

joined_keywords = '|'.join(escaped_keywords)

pattern = rf"\b({joined_keywords})\b|([^\w\s])"

temp = re.split(pattern, line)

In the pattern variable, lies well, the pattern. Now I need a pattern to treat everything within " and ' as a string, meaning even if symbols show up within the string, like this one: "hello, world!", it won’t split the , and !.

The pattern right now, if fed "hello, world!" it would return:

'"', 'hello', ',', 'world', '!', '"'

While the desired output would be:

'"', 'hello, world!', '"'

I tried this: "(.?)"|'(.?)' I tried to match the quoted string, but I have no idea what I’m doing since I used a regex playground to experiment. This did work though, capturing the " and ' but, who,e doing so, it also captured all the symbols inside of the string:
"Hello, World!" from this, it captured all instances of: ", , and ! which I don’t want, since the pattern is supposed to ignore the things within the strings, including ' and every other symbol.