r evaluate column of strings to determine if contain characters found in a vecto [duplicate]
This question already has answers here: Matching multiple patterns (6 answers) Use grepl to search either of multiple substrings in a text [duplicate] (2 answers) Closed 4 days ago. I have a data frame with variable that contains strings df <- data.frame(ID = 1:5, string = c(“blah, F21, blah”, “woop, woop, F25”, “G1, yes, yes”, […]
Remove all but the last instance of an underscore (_) in variable name
I would like to remove all but the final instance of an underscore _ from variable names in a data frame.
Remove all but the last instance of an underscore (_) in variable name
I would like to remove all but the final instance of an underscore _ from variable names in a data frame.
Remove all but the last instance of an underscore (_) in variable name
I would like to remove all but the final instance of an underscore _ from variable names in a data frame.
Split String that contains Date, Description, Amount and removeunnecessary characters
I need help in R extracting information such as Date, Description and Amount
and removing all unnecessary characters
extract values from string with random pattern
How can I extract 1.10E+93
, 1012055
, 1018598
,AOL
,WDF985
from the strings vector as below using pattern? I want to extract two times 1.10E+93
and 1012055
and one time other values i.e., extract one value for each string.