I need to process a string by regular expression in Python. My needs are:

I have 100s of files in a directory that are all in the same format like this:

Please I am trying to get a code in python that can look through a string like this one “986.80 CCF X $5.89 $5812.25” and return only the floating point number after the second “$” character. In this case it should return 5812.25

I have a line of code using regex to strip text between square brackets (inclusive). It works well. However, it keeps reporting

Why does the result for str.extract and str.extract_all differ? Should str.extract_all not return only the capture group, like str.extract does? import polars as pl #polars==0.20.30 dff = pl.DataFrame({‘a’: ‘Label: name, Value: John, Label: car, Value: Ford’}) (dff.with_columns(pl.col(‘a’).str.extract( r’Label:?(.*?) Value:’,1).alias(‘data1’), pl.col(‘a’).str.extract_all(r’Label:?(.*?) Value:’).list.get(0).alias(‘data2’) ) ) Results: data1: ” name,” data2: “Label: name, Value:” python regex

I have a string like this:

The source string is:

import re import urllib3 url = ‘https://bazaartracker.com/search?query=rough+ruby’ def extract_dynamic_numbers_from_url(url): http = urllib3.PoolManager() response = http.request(‘GET’, url) content = response.data.decode(‘utf-8′) pattern = r'<span class=”text-subtle-100″>([d.]+)s*coins</span>’ dynamic_numbers = re.findall(pattern, content) return dynamic_numbers print(extract_dynamic_numbers_from_url(url)) when i run it it print square brackets i tried to change pattern multiple times to narrow it down but that resulted in square brackets […]

I have a string like
“GGACATCGCGGTGGATCGAC”

Given two times in the form HH:MM, I want to filter logs containing all hours between the given hours.