I’m a bit confused about how regular expressions work with python methods. In particular, there’s an exercise from leetcode (https://leetcode.com/problems/patients-with-a-condition/description/) that is in which we have to find in the word DIAB1 exists in the string. Seems easy, right? However, I can’t seem to get the correct regular expression to fit the str.match() method. I ended using one of the posted solutions which uses str.contains() instead of str.match() but I’d like to get the full regular expression correct.

This question already has answers here: replace() method not working on Pandas DataFrame (10 answers) Closed 37 secs ago. I have the following dataset: meste = pd.DataFrame({‘a’:[’06/33′,’40/2′,’05/22′]}) a 0 06/33 1 40/2 2 05/22 And I want to remove the leading 0s in the text (06/33 to 6/33 for example). I tried this, without success: […]

I have the following dataset:

The following code allows me to successfully identify the 2nd and 3rd texts, and only those texts, in a pandas dataframe by search for rows that contain the word “cod” or “i”:

I am fairly new to Python and pandas. In my data cleaning, I would like to see the I performed previous cleaning steps correctly on a string column. In particular, I want to see where the strings begin and end, regardless of whether they have leading/trailing white space.

I am tasked with matching the products from a table to the Work Center they are supposed to be sent to. To do this, I have 2 tables: one contains the details about what product goes to what Work Center, and one containing the informations about the product to be made.

I have a string value (football score) in my Pandas dataset. I would like to extract the home goals and the away goals from this score.