I have a .txt file with all goals scored in the 2018 world cup, there are 169 lines in this file structured as:

Hi guys long story short I have a list of data structure that looks like this

class a(object): data={‘a’:’aaa’,’b’:’bbb’,’c’:’ccc’} def pop(self, key, *args): return self.data.pop(key, *args)#what is this mean. b=a() print b.pop(‘a’,{‘b’:’bbb’}) print b.data self.data.pop(key, *args) ←—— why is there a second argument? python dictionary 1 The pop method of dicts (like self.data, i.e. {‘a’:’aaa’,’b’:’bbb’,’c’:’ccc’}, here) takes two arguments — see the docs The second argument, default, is what pop returns […]

create an empty dictionary. Allow 4 friends to enter their favourite language as values and use keys as their names. Assume that the names are unique. case 2- if 2 friends have same name what will happen. case 3 – if two friends have same languages what will happen

I have a class that holds an unspecified number of dicts as variables. I want to provide methods that allow the user to easily append to any of the dicts while naming the corresponding variable, without having to check whether the variable was already created. Example for my goal:

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Task: Write a program to read dictionary items from a file and then write the inverted dictionary to a file.

I have a text file which contains duplicate car registration numbers with different values, like so:

I’m doing the Google course on Python, I’m a noob so apologies if it’s something obvious.

I have a list of pairs of integers [(int1, int2), (int3, int4) …], (or any immutable objects that can be used as dict keys).
I want a dict where each element is a unique element of the input list, and each value is a list of indices of the element in the list.
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