Calling the .replace() method on a Python DateTime object returns a new instance of a DateTime object instead of mutating the existing object. This seems to be a common pitfall when learning the method.

This question already has an answer here: Why does datetime.datetime.now() – datetime.datetime.now() equal to datetime.timedelta(-1, 86399, 999974)? (1 answer) Closed 1 hour ago. I’m working with python 3.12.4 and using the standard library datetime. I am expecting the difference between two datetime.now to be zero. Instead I get a number like 86399. import datetime print((datetime.datetime.now() […]

This question already has an answer here: Why does datetime.datetime.now() – datetime.datetime.now() equal to datetime.timedelta(-1, 86399, 999974)? (1 answer) Closed 1 hour ago. I’m working with python 3.12.4 and using the standard library datetime. I am expecting the difference between two datetime.now to be zero. Instead I get a number like 86399. import datetime print((datetime.datetime.now() […]

I have a simple datetime string:

The total second difference between 2 datetime objects set in different time zones but on the same date does not yield 0.0 in some circumstances.

I am working in Python and I have a .csv file that I’ve imported with two columns: a start date and and end date. I need to be able to convert both dates to a readable format in python so that it can calculate how many days between the two days. So an example would be:

I am playing around with the datetime API and i am trying to add a full year to today’s date. For some reason the code is throwing an error. This is what my code looks like

I have a list of dates formatted like so:

I’m getting Jan 1st when specifying a week number:

I’m getting Jan 1st when specifying a week number: