I have a question/doubt about the following snippet given n the book “C++ concurrency”. I want to know is there a technical reason(s) for putting the t.join() after the try catch block instead of putting it inside the try block.

I cannot really understand this behavior. Take a look at this piece of code:

How would one go about designing a C++ program that may create over 100 million atomic structs? I would like to ensure that each of this atomic struct won’t be written by two different threads. Each of these struct needs to persist throughout the program (since they may be modified in the future), but most likely they will only be used for a second.

I am trying to launch multiple threads which take in arguments startX , startY and endX ,endY

As a novice in C++ threads, I am a little bit confused. The std::async, for 1024 function calls, has almost the same duration like the 1024 calls of the same function. My intention is to demostrate (at least for me) that, by using threads, the execution of the 1024 add function, takes less time. Here is my code

The problem

I have a class that has a thread like so:

I am using NET 6 Web Api.

I am creating new threads and passing a parameter type Affectedinput. If I don’t use delay after thread creation then I see the statements are printed to console randomly in the thread function. This confuses me. I want to make sure that each thread is executed independently by using the delay without mixing the data send to the thread, is the following code good enough for production version?

#include <pthread.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <unistd.h> #define MIN_TID 300 #define MAX_TID 5000 #define NUM_TIDS (MAX_TID – MIN_TID + 1) unsigned char *bitset; // Global variable to hold the bitset pthread_mutex_t tid_mutex = PTHREAD_MUTEX_INITIALIZER; struct ThreadArgs { int min_sleep; int max_sleep; }; // Function to check if a bit is set (1) […]