In C++, why is the function qualifier applied to member functions in member function pointers, rather than to the class itself? [closed]
Closed 1 hour ago.
Dispose Pattern in C#: Implementing Dispose and GC.SuppressFinalize
I am studying the Dispose pattern in C#, and I understand that the Dispose method is used when there are unmanaged resources. For example, if I have an unmanaged resource in FirstClass, and FirstClass is contained within a Node class, I need to implement the Dispose method for both, right?
Dispose Pattern in C#: Implementing Dispose and GC.SuppressFinalize
I am studying the Dispose pattern in C#, and I understand that the Dispose method is used when there are unmanaged resources. For example, if I have an unmanaged resource in FirstClass, and FirstClass is contained within a Node class, I need to implement the Dispose method for both, right?
How can i install c++ compiler between this error [closed]
Closed yesterday.
Defining Array Default Parameters of a Class Constructor C++ [closed]
Closed 15 hours ago.
Template argumente deduction with overloaded function
I have the following code and am trying to understand why, in the first call to fun(), the compiler chooses the template instead of the non-template overload void fun(const int*).
Template argumente deduction with overloaded function
I have the following code and am trying to understand why, in the first call to fun(), the compiler chooses the template instead of the non-template overload void fun(const int*).
Template argumente deduction with overloaded function
I have the following code and am trying to understand why, in the first call to fun(), the compiler chooses the template instead of the non-template overload void fun(const int*).
Template argumente deduction with overloaded function
I have the following code and am trying to understand why, in the first call to fun(), the compiler chooses the template instead of the non-template overload void fun(const int*).
Class with deleted move assignment but with const copy assignment not move assignable
In the following test code, I understand why the class is still seen as move constructable, even though the default move constructor and assignment operator would not be implicitly generated by the compiler.