Machine code layout in the memory – Intel x86
I was asked to convert the following machine code to assembly in Intel syntax:
Why does Immediate to Memory-Direct require the ModRM byte?
I wanted to look at the object code for certain instructions to understand them better. My understanding of the modRM byte is that it is useful for the register-to-register opcode 8A
(8-bit) , as it is used to determine the destination and source registers/memory.