I have a following script.

#!/bin/bash

set -e
# set -x

##### Utility functions #######
is_pkg_installed() {
  local pkg_name="$1"
  if [[ -n "$VIRTUAL_ENV" ]]; then
    if pip show "$pkg_name" &>/dev/null; then
      return 0
    elif [[ -n "$POETRY_ACTIVE" ]]; then
      if python -c "import $pkg_name" &>/dev/null; then
        return 0
      else
        return 1
      fi
    else
      return 1
    fi
  else
    return 1
  fi

}

is_python_project() {
  local dir=$1
  local filename
  filename=$(basename "$dir")

  if [[ -f "$dir"/requirements.txt || -f "$dir"/pyproject.toml || "$filename" == *.py ]]; then
    return 0
  else
    for file in "$dir"/*; do
      if [[ -d "$file" ]]; then
        is_python_project "$file"
      fi
    done
  fi
  return 1
}

As you can see, this script only has functions, which aren’t called. When I try to source this file set -e, it exits the shell immediately.

I am not sure if my understanding of e option is correct, but I assumed, it exits the shell when command returns a non exit status and do get the exit status, a command should be executed first. But in my case, since commands are inside functions, they are not executed until I call the function, so when I source the script, it should source it without exiting.

If this is the intended behaviour and my understanding of e option is wrong, what is the work around to this i.e. exit the shell when an error is encountered and only when commands are executed. Preferably, I would just want to stop the script and not exit the shell, if that’s possible.