Consider the following example:

#include <optional>
#include <string>

struct S {
    std::string text = "hello";
};

std::optional<S> foo() {
    S s;
    return s;
}

std::optional<S> bar() {
    S s;
    return std::move(s);
}

Am I correct that foo and bar are identical since the compiler does RVO and automatically moves s when passing it to std::optional<S>?

So the general rule “Don’t move what you return” applies also when an implicit conversion will happen?