In the intel 8080 manual the DAA description says to follow these steps:

1. If the value of the least significant 4 bits of the
   accumulator is greater than 9 or if the AC flag
   is set, 6 is added to the accumulator.

2. If the value of the most significant 4 bits of the
   accumulator is now greater than 9, or if the CY
   flag is set, 6 is added to the most significant 4
   bits of the accumulator.

I’m not sure if the second step relies on the changes that happened to the accumulator during the 1st step, here is my try:

void DAA(State8080 *state) {
    uint8_t acc_val = state->registers[A];
    uint8_t val = 0;
    if (((state->registers[A] & 0x0F) > 0x09) || state->cc.ac) {
        val += 0x06;
        state->registers[A] += 0x06;
    }

    if (((state->registers[A] >> 4) > 0x09) || state->cc.cy) {
        val += 0x60;
        state->registers[A] += 0x60;
        state->cc.cy = 1;
    }
    uint8_t res = state->registers[A];

    _update_flag_z(state, res);
    _update_flag_s(state, res);
    _update_flag_p(state, res);
    _update_flag_ac_add(state, acc_val, val, false);

}