I have an output which has some hearders and some values under it. I want to capture everything which is after the header. i tried writing a pattern to match the header and take out lines after it. but the regex captures just one line after the header. how do i extend to multiple lines

my_str = '''
-------------------------------------
A     B      C     D    E    F      G
-------------------------------------
1     2      3      4    5   6     7
2     3      4      5    6   7     8
3     4      5      6    7   8     9
'''

import re
pat = '--+n.*n--+n(.*)'
match = re.search(pat, my_str, re.M)
if match:
    print(match.groups())

This captures just one line as below

('1     2      3      4    5   6     7',)

but i would like to capture everything after the pattern match so that my output should look like this

('1     2      3      4    5   6     7', '2     3      4      5    6   7     8','3     4      5      6    7   8     9')

i dont want to use findall and match the pattern because im worried if my output changes at any point in time like removal / adding some fields. so I want to extract everything after the pattern.