So, I am making a really simple Python interpreter. But, there is a part in the interpreter that checks for if statements. But, whenever I use this interpreted if statement, it checks every other indented line (which is what code should be executed if the statement is true). My code is shown below.

def tof(c):
    if eval(c) == True:
        return True
    elif eval(c) == False:
        return False

def interpret(code):
    lines = code.splitlines()
    for line in lines:
        if line.startswith("//") or line.strip() == "" or line.startswith("   "):
            continue
        if line.startswith("write(") and line.endswith(")"):
            if line[6] == '"' and line[-2] == '"':
                print(line[7:-2])
            elif line[6:-1].isdigit():
                print(line[6:-1])
            else: # not done yet (variables)
                v = line[6:-1]
                exec(f"print({v})")
        if line.startswith("if ") and line.endswith(" then"):
            one = line.split("if ")[1]
            c = one.split(" then")[0]
            if tof(c) == True:
                for x in lines:
                    if x.startswith("    "):
                        interpret(x.split("    ")[1])
            elif tof(c) == False:
                continue
        if line[2] == "=" or line[1] == "=": # not done yet (variables)
            if line[2] == "=":
                a = line.split(" = ")[0]
                b = line.split(" = ")[1]
                exec(f"{a} = {b}")

code = '''
if 1 + 1 == 2 then
    write("This should execute once!")
if 1 + 3 == 4 then
    // asterisk are there to tell which message is which.
    write("This should execute once! **")
'''

interpret(code)

I tried breaking the loop as soon as it sees an unindented piece of code, but if I put something like this:

if True then
    write("Hello, World!")
write("Stops here :(")
    write("Never gets here..")