I have a small code serving 2 pages and a 404 error page :

from http.server import BaseHTTPRequestHandler, HTTPServer
import time

hostName = "localhost"
serverPort = 8069

class MyServer(BaseHTTPRequestHandler):
    def do_GET(self):
        suitFlag = 0
       
        if self.path == '/':
            self.path = '/index.html'
            suitFlag = 1
            try: 
                file_to_open = open(self.path[1:]).read()
                self.send_response(200)
                self.send_header('Content-type', 'text/html')
                self.end_headers()
                self.wfile.write(bytes(file_to_open, 'utf-8'))
        
            except:
                self.send_response(404)
                self.send_header('Content-type', 'text/html')
                self.end_headers()
                file_to_send = open('sadly404.html').read()
                self.wfile.write(bytes(file_to_send, 'utf-8'))
        
        if self.path == '/dashboard':
            self.path = '/revenue.html'
            suitFlag = 1
            try:
                file_to_open = open(self.path[1:]).read()
                self.send_response(200)
                self.send_header('Content-type', 'text/html')
                self.end_headers()
                self.wfile.write(bytes(file_to_open, 'utf-8'))
            except:
                self.send_response(404)
                self.send_header('Content-type', 'text/html')
                self.end_headers()
                file_to_send = open('sadly404.html').read()
                self.wfile.write(bytes(file_to_send, 'utf-8'))

Now I want someone to visit /someHash/dashboard, I want to check from this code what the someHash is and then deliver relevant HTML page accordingly.

How can I do it?

I tried to use queryParams, but they can are not a feature I want to use to simplify my use case, These will be emmployees and they might be uncomfortable.

I want this someHash to be a part of URL not the query