I’m trying to run npm through ProcessBuilder.start(). However, in Windows at least, whenever I try to start the process without stating the full path of the executable, the invocation fails with “CreateProcess error=2”.

Sample code:

public class Main {
    public static void main(String[] args) {
        // Won't work
        invokeCommand(new String[] {"npm", "--version"});

        // Will work
        invokeCommand(new String[] {"C:\Program Files\nodejs\npm.cmd", "--version"});
    }

    private static void invokeCommand(String[] args) {
        System.out.println("INVOKING: " + String.join(" ", args));

        ProcessBuilder pb = new ProcessBuilder(args);

        try {
            Process p = pb.start();
            p.waitFor();

            dumpStdout(p);
        } catch (IOException e) {
            System.out.println(e.getMessage());
        } catch (InterruptedException e) {
            throw new RuntimeException(e);
        }

        System.out.println();
    }

    private static void dumpStdout(Process p) throws IOException {
        String line;
        BufferedReader reader = new BufferedReader(new InputStreamReader(p.getInputStream()));

        while ((line = reader.readLine()) != null) {
            System.out.println("STDOUT: " + line);
        }

        reader.close();
    }
}

Why is it so? Is it because npm is a batch command? That’s very inconvenient, not to say inconsistent with other programs like java or node that will run just fine without their full paths. Thank you.