.model small
.stack 100h

.data
input_buffer1 db 10 DUP (‘$’) ; Define a buffer to store the first input string
input_buffer2 db 10 DUP (‘$’) ; Define a buffer to store the second input string
message1 db ‘Enter the first integer: $’ ; Prompt message for the first input
message2 db ‘Enter the second integer: $’ ; Prompt message for the second input
newline db 13, 10, ‘$’ ; Newline character to print a newline
result_message db ‘The sum is: $’ ; Message for printing the sum

.code
main proc
mov ax, @data ; Load the address of the data segment into AX
mov ds, ax ; Set DS to point to the data segment

; Prompt for the first input
mov ah, 09h              
mov dx, offset message1
int 21h

; Read the first input
mov ah, 0Ah              ; Function to read a string
mov dx, offset input_buffer1
int 21h                  ; Call interrupt 21h     


  ; Print a newline character
mov ah, 09h
mov dx, offset newline
int 21h

; Prompt for the second input
mov ah, 09h              
mov dx, offset message2
int 21h                  



; Read the second input
mov ah, 0Ah              ; Function to read a string
mov dx, offset input_buffer2
int 21h                  ; Call interrupt 21h

; Convert the first input to integer
mov si, offset input_buffer1 + 2   ; Skip the first two bytes (length and '$')
mov al, [si]                        ; Load the first character
sub al, '0'                         ; Convert ASCII character to integer
mov bl, al                          ; Save the integer in BL

; Convert the second input to integer
mov si, offset input_buffer2 + 2   ; Skip the first two bytes (length and '$')
mov al, [si]                        ; Load the first character
sub al, '0'                         ; Convert ASCII character to integer
add bl, al                          ; Add the second input (AL) to the first input (BL)


  ; Print a newline character
mov ah, 09h
mov dx, offset newline
int 21h

; Print the sum
mov ah, 09h
mov dx, offset result_message
int 21h

; Convert the sum to ASCII and print
mov dl, bl              ; Move the result to DL for printing
add dl, '0'             ; Convert integer to ASCII character
mov ah, 02h             ; Function to print a character
int 21h                 ; Call interrupt 21h

end main

; Convert the sum to ASCII and print
mov dl, bl ; Move the result to DL for printing
add dl, ‘0’ ; Convert integer to ASCII character
mov ah, 02h ; Function to print a character
int 21h ; Call interrupt 21h
I think problem here, I cant figure how can I print more than one digit.