The following is my code:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Main {
    public static void main(String args[]) {
        String pageText = "Other Strings 9.5.1 My Other Strings";
        String pageText2 = "Other Strings 9.3.1.1.1 My Other Strings";
        Pattern anyServicePattern = Pattern.compile("(\d+\.){2}[0-9]\s+[a-zA-Z]+");
        Matcher anyServiceMatcher = anyServicePattern.matcher(pageText);
        if (anyServiceMatcher.find()) {
            System.out.println("Found");
        } else {
            System.out.println("Not Found");
        }
        
        Matcher anyServiceMatcher2 = anyServicePattern.matcher(pageText2);
        if (anyServiceMatcher2.find()) {
            System.out.println("Found");
        } else {
            System.out.println("Not Found");
        }
    }
}

It prints:
Found
Found

I want it to print
Found
Not Found

i.e. I want the regular expression should match the pattern <whatever characters><any number><dot><any number><dot><any number><single space><whatever characters>

I tried many combinations, but to my high surprise couldn’t crack it. What is the correct expression?

Here is the jdoodle link: https://www.jdoodle.com/ia/14IW