I have a function where TypeScript can infer the return type based on the type of the input parameters.

//typescript can automatically infer the type of "result"
let result = handle(container, child);

The function also allows you to specify the type of the input functions explicitly using generics.

//you can also specify the types using generics:
let result = handle<MyContainer, MyChild>(container, child);

Is it possible to skip over the declaration of MyContainer and only specify the second parameter MyChild, while having TypeScript still determine the type of the first parameter without me specifying it:

let result = handle<skipMe, MyChild>(container, child);

What can I put in place of skipMe? I can’t put unknown or any because then TypeScript thinks the type of the first parameter is any.