In relation R(C,D,E) F={CD->E, C->D} is E partially determined?
C+ derives E as an attribute but it happens with the help of CD->E.
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If (C implies D) and (C and D implies E)
then I would say, that also (C -> E)
Reasoning:
- If you know C, then you also have knowledge over D.
- But now you have knowledge over C and D and this implies E.
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