Problem statement: Defines a function apply_pattern_to_list(), that takes three arguments. You can assume that
the first argument is a list of integers,
the second argument is a nonempty string (the pattern) consisting of + and – only (it is set to ‘+-‘ by default), and
the third argument is either True or False (it is set to True by default).
If the third argument is True then is removed, again and again, the leftmost element in that prevents what is left of, from the beginning up to that element, to be consistent with the pattern, read from left to right. If the third argument is False then is removed, again and again, the rightmost element in that prevents what is left of, from that element up to the end, to be consistent with the pattern, read from right to left.
A + in the pattern is for two successive elements the second of which is strictly greater than the first one.
A – in the pattern is for two successive elements the second of which is strictly smaller than the first one.
The pattern is to be thought of as circular (as if wrapping around), so there is no difference between a pattern and many concatenations of that pattern (e.g., there is no difference between the patterns ‘+’, ‘++’, ‘+++’, …, and there is no difference between the patterns ‘+-‘, ‘+-+-‘, ‘+-+-+-‘…
The function returns a dictionary for everything that has been removed from: where in the created list an element has been removed (the key, as a positive index when processing list and pattern from left to right, as a negative index when processing list and pattern from right to left), and what that element is (the value).
The function modifies the list provided as argument and returns a dictionary.
def apply_pattern_to_list(L, pattern='+-', from_start=True):
def is_consistent(a, b, p):
return (p == '+' and a < b) or (p == '-' and a > b)
result = {}
pattern = pattern * (len(L) // len(pattern) + 1)
if from_start:
i = 0
while i < len(L) - 1:
if not is_consistent(L[i], L[i+1], pattern[i % len(pattern)]):
result[i+1] = L.pop(i+1)
else:
i += 1
else:
i = len(L) - 1
while i > 0:
if not is_consistent(L[i-1], L[i], pattern[(len(L)-i) % len(pattern)]):
result[i-len(L)] = L.pop(i-1)
else:
i -= 1
return result
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- Function definition:
This defines the function with the three parameters as specified in the problem statement.
2)Helper function:
This checks if two adjacent elements (a and b) are consistent with the pattern p.
- Initialization:
Creates an empty dictionary to store removed elements, and extends the pattern to cover the entire list length.
4)Main logic:
The code then branches based on the from_start parameter:
This iterates through the list, checking each pair of adjacent elements. If they’re inconsistent with the pattern, it removes the second element and adds it to the result dictionary.
This does the same thing but starts from the end of the list and moves backwards.
- Return statement:
Returns the dictionary of removed elements.
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