Let’s say I have type Foo:

type Foo = 'apple' | `a.${number}` | `a.${number}.c`

Eventually I want to convert it to Boo:

type Boo = ReplaceTemplateWithLiteral<Foo>
// 'apple' | 'a.${number}' | 'a.${number}.c'

I know that I can extract string type that includes ${number} by:

Extract<Foo, `${string}.${number}` | `${string}.${number}.${string}`>
// `a.${number}` | `a.${number}.c`

But I don’t know how to convert it to 'a.${number}' | 'a.${number}.c' which is just string literals.

Is this even possible?