I want to open the particular screen of my app when I click on the email link. I have given the scheme and host in the android manifest file like below.

            <intent-filter android:autoVerify="true">
                <action android:name="android.intent.action.VIEW" />
                <category android:name="android.intent.category.DEFAULT" />
                <category android:name="android.intent.category.BROWSABLE" />
                <data android:scheme="http" android:host="aaaa.com" />
                <data android:scheme="aaaa" />
            </intent-filter>

So when I click on the link, it is redirecting to my app. But it is not opening the specific screen which I want. I have tried the below code. But it keeps opening the screen which is already open.

void main() {
  runApp(const MyApp());
}

class MyApp extends StatelessWidget {
  const MyApp({super.key});

  // This widget is the root of your application.
  @override
  Widget build(BuildContext context) {
    return MaterialApp.router(
      title: 'MyApp',
      theme: ThemeData(
        useMaterial3: true,
        colorScheme: ColorScheme.fromSeed(
          seedColor: const Color.fromRGBO(26, 49, 60, 1),
        ),
      ),
      routerConfig: router,
    );
  }
}

GoRouter router = GoRouter(
  routes: [
    GoRoute(
        path: '/',
        name: 'email_screen',
        pageBuilder: (context, state) {
          return MaterialPage(child: EmailScreen(

          ));
        }
    ),
    GoRoute(
        path: '/',
        name: 'reset_screen',
        pageBuilder: (context, state) {
          return MaterialPage(child: ResetScreen(

          ));
        }
    ),
  ],

);

I want to open the reset_screen. But it is not working. I am new to flutter. Please someone help me to solve this issue. Thanks in advance.