I have a list like this:

list1 = [
    {'id': 'ABC', 'created_at': datetime.date(2024, 8, 1, 11, 22, 3)},
    {'id': 'ABC', 'created_at': datetime.date(2024, 8, 2, 11, 22, 3)},
    {'id': 'ABC', 'created_at': datetime.date(2024, 8, 3, 11, 22, 3)},
    {'id': 'ABC', 'created_at': datetime.date(2024, 8, 5, 11, 22, 3)},
    {'id': 'BAC', 'created_at': datetime.date(2024, 7, 25, 18, 22, 3)},
    {'id': 'BAC', 'created_at': datetime.date(2024, 7, 26, 18, 22, 3)},
    {'id': 'BAC', 'created_at': datetime.date(2024, 8, 1, 18, 22, 3)},
    {'id': 'BAC', 'created_at': datetime.date(2024, 8, 5, 11, 22, 3)},
    {'id': 'CAB', 'created_at': datetime.date(2024, 8, 1, 6, 53, 3)},
    {'id': 'CAB', 'created_at': datetime.date(2024, 8, 1, 17, 53, 3)},
    {'id': 'CAB', 'created_at': datetime.date(2024, 8, 2, 11, 53, 3)},
    {'id': 'CAB', 'created_at': datetime.date(2024, 8, 5, 11, 22, 3)},
]

The list is sorted by id and created_at, so it’s not needed to sort again.

If it were one id with no repeats, I knew I could do this:

output = 'n'.join([f"ID: {l['id']}, Created At: {l['created_at']}" for l in list1])

But regarding the following expected output, I don’t know the how-to:

[
    {'id': 'ABC', 'start': datetime.date(2024, 8, 3, 11, 22, 3), 'end': datetime.date(2024, 8, 5, 11, 22, 3)},
    {'id' 'BAC', 'start': datetime.date(2024, 8, 1, 18, 22, 3), 'end': datetime.date(2024, 8, 5, 11, 22, 3)},
    {'id' 'CAB', 'start': datetime.date(2024, 8, 2, 11, 53, 3), 'end': datetime.date(2024, 8, 5, 11, 22, 3)},
]

I’m going to print the one before last column date of each id as start, and the last one as end.