I want to pass the “--var-options” into the “file.sh” as follows:

/path/to/file.sh --var-options "arg1" "-arg2" "--arg3" "arg4" --foo-option "foo_1" "foo_2" "foo_3" --bar-option "bar_1" "bar_2"

Here is the format of “--var-options“, “--foo-option“, and “--bar-option“:

--var-options "--arg1" "--arg2" "--arg3" "all_string_must_be_in_double_quotes"
--foo-option "foo_1" "foo_2" "foo_3"
--bar-option "bar_1" "bar_2"

Here are the possible values for “--var-options“:

--var-options "--arg1" "--arg2" "--arg3" "all_string_must_be_in_double_quotes"
--var-options "--arg1" "all_string_in_double_quotes"
--var-options "--at-less-one_arg"
--var-options "any_length_1" ... "all_string_must_be_in_double_quotes"

Here is the file.sh script for parsing the command line:

declare -a var_list=()

while true
do
    case "$1" in
        --var-options)
            # How to get args for "--var-options" here?
            
            # If the args are 2, then:
            echo "2 args for --var-options are: $1, $2"
            shift 3
            
            # But the length of "--var-options" is dynamically and at less one arg:
            # How to get: "$1" "$2" "$3" ... "$n" here?
            # How to determine the count of args of "--var-options"
            shift <var-length-count>
            
            # Put all args related to "--var-options" into the "var_list" here
            ;;
        --foo-option)
            echo "3 args for foo are: $1, $2, $3"
            shift 4
            ;;
        --bar-option)
            echo "2 args for bar are: $1, $2"
            shift 3
            ;;
    esac
done

How to get all args for the “--var-options” and put them into the “var_list“?