I don’t understand how to free() the strings in my array char**
When I try to do it in this code I got a segfault and 40 bytes lost with valgrind

int     main(void)
{
    char    **strs;
    char    *ret;
    char    *sep = "...";
    int     size = 4;
    int     i = 0;

    strs = malloc(sizeof(char *) * 4);
    while (i < 4)
    {
        strs[i] = malloc(sizeof(char) * 10);
        i++;
    }
    strs[0] = "Why";
    strs[1] = "it";
    strs[2] = "doesn't";
    strs[3] = "work";

    ret = foofoo(size, strs, sep);
    printf("%sn", ret);

    i = 0;
    while (i < size)
    {
        free(strs[i]);
        i++;
    }
    free(strs);
    free(ret);
    
    return (0);
}

If I remove this part, no error will occur but if I compile with gcc -g and execute with valgrind I definitely lost 40 bytes because i don’t free() the strings.

    while (i < size)
    {
        free(strs[i]);
        i++;
    }

Can you explain me please.
Thx