I have JSON that represents ConfigValue (parameter param is representation of ConfigParameter):

{"value":10,"param":{"name":"size","type":"BIG_DECIMAL","class":"java.math.BigDecimal","required":true}}

To de/serialize ConfigParameter I use serializer class:

public class ConfigParamSerializer extends StdSerializer<ConfigParameter> {

  public ConfigParamSerializer() {
    this(null);
  }

  public ConfigParamSerializer(Class<ConfigParameter> t) {
    super(t);
  }

  @Override
  public void serialize(
      ConfigParameter value, JsonGenerator jsonGenerator, SerializerProvider serializerProvider)
      throws IOException {

    jsonGenerator.writeStartObject();
    jsonGenerator.writeObjectField("name", value.getName());
    jsonGenerator.writeObjectField("type", value.getType());
    jsonGenerator.writeObjectField("class", value.getType().getClassName());
    jsonGenerator.writeObjectField("required", value.isReguired());
    jsonGenerator.writeEndObject();

  }
}

and deserialization class:

public class ConfigParamDeserializer extends StdDeserializer<ConfigParameter> {

  public ConfigParamDeserializer() {
    this(null);
  }

  public ConfigParamDeserializer(Class<ConfigParameter> t) {
    super(t);
  }

  @Override
  public ConfigParameter deserialize(
      JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {

    final JsonNode node = jsonParser.getCodec().readTree(jsonParser);

    String name = node.get("name").asText();
    ParamType type = ParamType.fromCodeName(node.get("type").asText());
    boolean required = ObjectUtils.safeBoolean(node.get("required").asText());

    return Assembler.create(name,type,required);
  }
}

Q: Now I would like to use these classes to help deserialize mentioned ConfigValue JSON; I am not sure how to call ConfigParamDeserializer to deserialize JSON to get instance of ConfigParameter class?