I ask for your help. I need to compare an array of tokens with a char using the if statement. But in the array I also have a string, the code is this:
char bho(char** Token){
char* token = (char*)Token;
enum TokenType type;
int len_token = strlen(token);
for (int i = 0; i < len_token; i++){
if(Token[i] == NULL){
continue;
}else if (Token[i] == '='){
type = Equals;
printf("{value: %s, type: %d}n", Token[i], type);
} else {
printf("{value: %s}n", Token[i]);
}
}
}
int main(void){
char input[] = "Ciao = l";
char** array;
array = tokenizer(input);
bho(array);
}
tokenizer() is a function that splits the input string and put the parts into an array. The enum TokenType is an enum that I need to categorize the type of all the content of the array.
The problem is that my program has the output of:
output:
{value: Ciao}
{value: =}
{value: l}
but the output it has to give me is:
output:
{value: Ciao}
{value: =, type: 4}
{value: l}
I do:
for (int i = 0; i < len_token; i++){
if(Token[i] == NULL){
continue;
} else if(Token[i] == '='){
type = Equals;
printf("{value: %s, type: %d}n", Token[i], type);
} else {
printf("{value: %s}n", Token[i]);
}
}
but give me the error: comparison between pointer and integer.
I tried various methods but can’t make it work.
Sorry if I wrote with incorrect grammar but i did fatigue with the write in English.
6
There were several ways that your posted source code used types that needed a few changes.
Since your post did not include the entire code such as the source for the function tokenizer(), I made an assumption or two.
Here is a solution with those assumptions and works with the test data I put together.
#include <stdio.h>
#include <string.h>
// added type since it's not in the post.
enum { Unknown = 0, Equals = 4 } TokenType;
char bho(char** Token) {
enum TokenType type = Unknown;
// go through the array of strings checking each
// string to determine the token's type.
// we assume the last entry is a guard value of NULL
// indicate the end of the array.
for (; *Token != NULL; Token++) {
if (strcmp (*Token, "=") == 0) {
type = Equals;
printf("{value: %s, type: %d}n", *Token, type);
}
else {
printf("{value: %s}n", *Token);
}
}
return 0;
}
int main(void) {
char input[] = "Ciao = l";
// create sample test data This assumes that the function
// tokenizer creates an array of pointers to strings and
// the last item in the array is a NULL pointer indicating
// no more data.
char* array[] = { "Ciao", "=", "1", NULL };
// comment out this unknown function in order to use
// the test data.
// array = tokenizer(input);
bho(array);
return 0;
}