I found some ways to pass external shell variables to an awk
script, but I’m confused about '
and "
.
First, I tried with a shell script:
$ v=123test
$ echo $v
123test
$ echo "$v"
123test
Then tried awk:
$ awk 'BEGIN{print "'$v'"}'
$ 123test
$ awk 'BEGIN{print '"$v"'}'
$ 123
Why is the difference?
Lastly I tried this:
$ awk 'BEGIN{print " '$v' "}'
$ 123test
$ awk 'BEGIN{print ' "$v" '}'
awk: cmd. line:1: BEGIN{print
awk: cmd. line:1: ^ unexpected newline or end of string
I’m confused about this.
5
#Getting shell variables into
awk
may be done in several ways. Some are better than others. This should cover most of them. If you have a comment, please leave below. v1.5
Using -v
(The best way, most portable)
Use the -v
option: (P.S. use a space after -v
or it will be less portable. E.g., awk -v var=
not awk -vvar=
)
variable="line onenline two"
awk -v var="$variable" 'BEGIN {print var}'
line one
line two
This should be compatible with most awk
, and the variable is available in the BEGIN
block as well:
If you have multiple variables:
awk -v a="$var1" -v b="$var2" 'BEGIN {print a,b}'
Warning. As Ed Morton writes and as seen in the above example, the shell variable is expanded by the shell before awk then sees its content as awk -v var='line onenline two'
and so any escape sequences in the content of that shell variable will be interpreted when using -v
, just like they are for every other form of assignment of a string to a variable in awk, e.g. awk 'BEGIN{var="line onenline two"} {...}'
or awk '{...}' var='line onenline two'
, and so n
becomes a literal LineFeed character and not the 2-character string n
. For example, given a variable like:
$ variable='atbn$ckd'
awk would expand the escape sequences in the assignment:
$ awk -v var="$variable" 'BEGIN{ printf "%sn", var }'
awk: warning: escape sequence `k' treated as plain `k'
a b
$ckd
If that’s not what you want then, if your shell (e.g. bash
) and locale (e.g. LC_ALL=C
) support it then you can have backslashes treated literally by using shell parameter substitution to escape any backslashes:
$ awk -v var="${variable//\/\\}" 'BEGIN{ printf "%sn", var }'
atbn$ckd
or by using ENVIRON[]
or access it via ARGV[]
(see below).
You cannot use -v var="$(printf '%q' "$variable")"
for this as that would also escape $
s, nor can you use -v var="${variable@Q}"
as that would just add '
s around "$variable"
and the escape sequences would still be interpreted by awk. That’s because those 2 approaches both escape chars according to shell syntax for providing command input, not awk syntax for assigning strings to variables.
PS If you have vertical bar or other regexp meta characters as separator like |?(
etc, they must be double escaped. Example 3 vertical bars |||
becomes -F'\|\|\|'
. You can also use -F"[|][|][|]"
.
Example on getting data from a program/function in to
awk
(here date is used)
awk -v time="$(date +"%F %H:%M" -d '-1 minute')" 'BEGIN {print time}'
Example of testing the contents of a shell variable as a regexp:
awk -v var="$variable" '$0 ~ var{print "found it"}'
Variable after code block
Here we get the variable after the awk
code. This will work fine as long as you do not need the variable in the BEGIN
block:
variable="line onenline two"
echo "input data" | awk '{print var}' var="${variable}"
or
awk '{print var}' var="${variable}" file
- Adding multiple variables:
awk '{print a,b,$0}' a="$var1" b="$var2" file
- In this way we can also set different Field Separator
FS
for each file.
awk 'some code' FS=',' file1.txt FS=';' file2.ext
- Variable after the code block will not work for the
BEGIN
block:
echo "input data" | awk 'BEGIN {print var}' var="${variable}"
Here-string
Variable can also be added to awk
using a here-string from shells that support them (including Bash):
awk '{print $0}' <<< "$variable"
test
This is the same as:
echo "$variable" | awk '{print $0}'
printf '%s' "$variable" | awk '{print $0}'
P.S. this treats the variable as a file input.
ENVIRON
input
As TrueY writes, you can use the ENVIRON
to print Environment Variables.
Setting a variable before running AWK, you can print it out like this:
export X=MyVar
awk 'BEGIN{print ENVIRON["X"],ENVIRON["SHELL"]}'
MyVar /bin/bash
or for a non-exported variable:
x=MyVar
x="$x" awk 'BEGIN{print ENVIRON["x"],ENVIRON["SHELL"]}'
MyVar /bin/bash
ARGV
input
As Steven Penny writes, you can use ARGV
to get the data into awk:
v="my data"
awk 'BEGIN {print ARGV[1]}' "$v"
my data
To get the data into the code itself, not just the BEGIN:
v="my data"
echo "test" | awk 'BEGIN{var=ARGV[1];ARGV[1]=""} {print var, $0}' "$v"
my data test
Variable within the code: USE WITH CAUTION
You can use a variable within the awk
code, but it’s messy and hard to read, and as Charles Duffy
points out, this version may also be a victim of code injection. If someone adds bad stuff to the variable, it will be executed as part of the awk
code.
This works by extracting the variable within the code, so it becomes a part of it.
If you want to make an awk
that changes dynamically with use of variables, you can do it this way, but DO NOT use it for normal variables.
variable="line onenline two"
awk 'BEGIN {print "'"$variable"'"}'
line one
line two
Here is an example of code injection:
variable='line onenline two" ; for (i=1;i<=1000;++i) print i"'
awk 'BEGIN {print "'"$variable"'"}'
line one
line two
1
2
3
.
.
1000
You can add lots of commands to awk
this way. Even make it crash with non valid commands.
One valid use of this approach, though, is when you want to pass a symbol to awk to be applied to some input, e.g. a simple calculator:
$ calc() { awk -v x="$1" -v z="$3" 'BEGIN{ print x '"$2"' z }'; }
$ calc 2.7 '+' 3.4
6.1
$ calc 2.7 '*' 3.4
9.18
There is no way to do that using an awk variable populated with the value of a shell variable, you NEED the shell variable to expand to become part of the text of the awk script before awk interprets it. (see comment below by Ed M.)
Extra info:
Use of double quote
It’s always good to double quote variable "$variable"
If not, multiple lines will be added as a long single line.
Example:
var="Line one
This is line two"
echo $var
Line one This is line two
echo "$var"
Line one
This is line two
Other errors you can get without double quote:
variable="line onenline two"
awk -v var=$variable 'BEGIN {print var}'
awk: cmd. line:1: onenline
awk: cmd. line:1: ^ backslash not last character on line
awk: cmd. line:1: onenline
awk: cmd. line:1: ^ syntax error
And with single quote, it does not expand the value of the variable:
awk -v var='$variable' 'BEGIN {print var}'
$variable
More info about AWK and variables
Read this faq.
3
It seems that the good-old ENVIRON
awk built-in hash is not mentioned at all. An example of its usage:
$ X=Solaris awk 'BEGIN{print ENVIRON["X"], ENVIRON["TERM"]}'
Solaris rxvt
11
You could pass in the command-line option -v
with a variable name (v
) and a value (=
) of the environment variable ("${v}"
):
% awk -vv="${v}" 'BEGIN { print v }'
123test
Or to make it clearer (with far fewer v
s):
% environment_variable=123test
% awk -vawk_variable="${environment_variable}" 'BEGIN { print awk_variable }'
123test
3
You can utilize ARGV:
v=123test
awk 'BEGIN {print ARGV[1]}' "$v"
Note that if you are going to continue into the body, you will need to adjust
ARGC:
awk 'BEGIN {ARGC--} {print ARGV[2], $0}' file "$v"
1
I had to insert date at the beginning of the lines of a log file and it’s done like below:
DATE=$(date +"%Y-%m-%d")
awk '{ print "'"$DATE"'", $0; }' /path_to_log_file/log_file.log
It can be redirect to another file to save
2
I just changed @Jotne’s answer for “for loop”.
for i in `seq 11 20`; do host myserver-$i | awk -v i="$i" '{print "myserver-"i" " $4}'; done
1
Pro Tip
It could come handy to create a function that handles this so you dont have to type everything every time. Using the selected solution we get…
awk_switch_columns() {
cat < /dev/stdin | awk -v a="$1" -v b="$2" " { t = $a; $a = $b; $b = t; print; } "
}
And use it as…
echo 'a b c d' | awk_switch_columns 2 4
Output:
a d c b
1