I have an object with string as keys. But, I don’t want it to be string. I want the key strings to be that exact value of the object. I have to type the value of that object as well to follow certain rules. Here is an example,

type ObjectValueType = {
  checked: boolean;
  fields: Path<Camera>[];
};

type ObjectType = Record<string, ObjectValueType>;

const Object: ObjectType = {
  camera_stream_endpoint: {
    checked: false,
    fields: ['camera_stream_endpoint'],
  },
  layout_image: {
    checked: false,
    fields: ['layout_image'],
  },
};

In the above object, I have created a typescript type ObjectType which has string as key and ObjectValueType as value. I don’t want key to be string. I want the key to be the exact keys of the Object (camera_stream_endpoint or layout_image or rest). How do I infer this key?

I don’t want to create a union type of the object key because that object is an extremely long object with a lot of keys. So, I would prefer TypeScript infer that key from the created object.

One thing I tried is using assertion as const like so

const Object = {
  camera_stream_endpoint: {
    checked: false,
    fields: ['camera_stream_endpoint'],
  },
  layout_image: {
    checked: false,
    fields: ['layout_image'],
  },
} as const;

The above achieves the desired outcome for the keys. But, now, I can put whatever I want for the value. Example, I could easily mess up the fields which should follow the defined type Path<Camera>. TypeScript won’t complain at all for the wrong values.

I want to type the keys and values of the object. Keys should be inferred from the created variable and value will have its own type definition. Is it possible?