When I define a TextView in xml, how do I add a new line to it? n seems not to work.
<TextView
android:id="@+id/txtTitlevalue"
android:text="Line1 -nLine2"
android:layout_width="54dip"
android:layout_height="fill_parent"
android:textSize="11px" />
2
Don’t trust the Visual editor.
Your code does work in the emu.
2
Try:
android:lines="2"
n should work.
1
try System.getProperty("line.separator");
0
I think this has something to do with your HTM.fromHtml(subTitle) call: a “n” doesn’t mean bupkis to HTML. Try <br/> instead of “n”.
1
Tried all the above, did some research of my own resulting in the following solution for rendering line feed escape chars:
string = string.replace("\n", System.getProperty("line.separator"));
-
Using the replace method you need to filter escaped linefeeds (e.g.
'\n') -
Only then each instance of line feed
'n'escape chars gets rendered into the actual linefeed
For this example I used a Google Apps Scripting noSQL database (ScriptDb) with JSON formated data.
Cheers 😀
2
First, put this in your textview:
android:maxLines="10"
Then use n in the text of your textview.
maxLines makes the TextView be at most this many lines tall. You may choose another number 🙂
0
Make sure your n is in "n" for it to work.
<TextView
android:id="@+id/txtTitlevalue"
android:text="Line1: rn-Line2rn-Line3"
android:layout_width="54dip"
android:layout_height="fill_parent"
android:textSize="11px" />
I think this will work.
My 2 cents, using Android TV.
Add n in XML strings, while reading:
public void setSubtitle(String subtitle) {
this.subtitle = subtitle.replace("\n", System.getProperty("line.separator"));
}
I just solve the same problem, put below attributes in xml
android:lines="2" android:maxLines="4" android:singleLine="false"
work.Html.fromHtml("text1 <br> text2").toString() also work.
2
This solved my problem.
stringVar.replaceAll("\\n", "\n");
0
One way of doing this is using Html tags::
txtTitlevalue.setText(Html.fromHtml("Line1"+"<br>"+"Line2" + " <br>"+"Line3"));
Also you can add <br> instead of n.
And then you can add text to TexView:
articleTextView.setText(Html.fromHtml(textForTextView));
1
System.getProperty("line.separator"); this work for me.
1
If you debug, you will see that the string is actually " r n" or " n", ie, it is escaped. So if you massage that string, to get rid of the extra , you will have your solution. This is true especially if you are reading from a database.
0
You need to put the "n" in the strings.xml file not within the page layout.
1
Need to keep
1.android:maxLines="no of lines"
2.And use n for getting of the next Lines
For me the solution was to add the following line to the layout:
<LinearLayout
xmlns:tools="http://schemas.android.com/tools"
...
>
And n shows up as a new line in the visual editor. Hope it helps!
6
android:text="Previous Line
Next Line"
This will work.
2
You need to put n in the file string.xml
<string name="strtextparkcar">press Park my Car to store location n</string>
Try this:
android:text="Lorem Ipsum nDolor Ait Amet nLorem Ipsum"
1
This works fine. Check it for your app.
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Text 1nText 2nText 3"/>
Just try:
Textview_name.settext("something n new line "):
In Java file.
1
RuDrA05’s answer is good, When I edit the XML on eclipse it does not work, but when I edit the XML with notepad++ it DOES work.
The same thing is happening if I read a txt file saved with eclipse or notepad++
Maybe is related to the encoding.
Side note: Capitalising text using
android:inputType="textCapCharacters"
or similar seems to stop the n from working.
Make sure you are using your_package.R
and not android.R
for the new line in TextView just add n in middle of your text
it works..
3
If the TextView is in any Layout (LinearLayout for example), try to change the orientation attribute to vertical as
android:orientation="vertical" for the layout or change the TextView attribute android:singleLine="true" to create a new line after it.
Programatically: myTV.setText(“My Text” + “n” + myString);
Create a string in your stings.xml
<resources>
...
<string name="new_line">u000A</string>
</resources>
Then in you code reference the string
val linkString = "This is in the first line.${getString(R.string.new_line)}This is on the second line."
0