A string literal when passed to a function will be deduced to be first a const char (&)[] array first, and then if not function is suitable it will decay to a const char*. So I thought that the following would work, however the const char* function is still being called:

#include <iostream>
//
struct MyString
{
    MyString() { }
    template <typename ...Ts>
    MyString(Ts&& ... args)
    {
        append(std::forward<Ts>(args)...);
    }

    void append(const char* str)
    {
        /* NOW STRING LENGTH WILL HAVE TO BE CALLED ON THIS */
        std::cout << "append const char* calledn";
    }
    template <int N>
    void append(const char(&arr)[N])
    {
        /* I KNOW THE SIZE OF THE STRING HERE */
        std::cout << "append arr[N] called n";

    }

};
int main()
{
    MyString s;// { "Hello" };
    s.append("Imagine some really long string");
}

I guess this is because non-template functions are preferred first. Can I make it prefer the array one without deleting the const char*?