This is a recursive function in C (function call itself) the Main case is:
and is returned a value of variable “i” that must be 6 but is 1 as explaned:

if(i==6){return i;} but the value returned is 1 not 6…
note that i must be == 6 to exevute
return…

Here is the code:

#include<stdio.h>

int func1(int i){
    
    if(i == 6) {  // Base Case
        printf("nEnd1");
        return i;
    }
        
    printf("%d ", i);
    func1(i + 1);
    // printf("nEnd1");
    return i;
    
}

int main()
{
    printf("n%d", func1(1));
    return 0;
}

I receive 1 as i value instead of 6.

this is my Output:
1 2 3 4 5
End1
1

Expected Output:
1 2 3 4 5
End1
6

I don’t know where to throw the head…

Any Solution?

The following link open a new website page click here↗???? to view the code run.

(this qestion follows what asked in “C Multiple Func() printf – With no Reason”.