Why is the operators << and >> called in base class if they are defined as ‘friend’ when calling << and >> in parent class?

Code:

#include <iostream>
#include <memory>
#include <vector>

using namespace std;

class Baza
{
protected:
    int n;
public:
    Baza() { cout << "Bn"; }
    virtual ~Baza() { cout << "~Bn"; }

    friend istream& operator>>(istream& in, Baza& b);
    friend ostream& operator<<(ostream& out, const Baza& b);
};

istream& operator>>(istream& in, Baza& b)
{
    cout<<"op >>"<<endl;
    return in;
}

ostream& operator<<(ostream& out, const Baza& b)
{
    cout<<"op<<"<<endl;
    return out;
}

class Derivata : public Baza
{
public:
    Derivata() { cout << "Dn"; }
    ~Derivata() { cout << "~Dn"; }


};



int main()
{
    vector<Derivata> v;
    v.push_back(new Derivata);

// works
    Derivata d;
    cin>>d;
    cout<<d;

    return 0;
}

Is c++ compiler creating a operators that calls the base class method’s operator by default when compiling?