So I have this Fortran code:

xo  = xo  +  delta
      no  = no  +  nx
      mo  = mo  +  mx
      Ro  = Ro  +  Rx
      R1o = R1o +  R1x
      Po  = Po  +  Px
      Mso = Mso +  Msx
      Mbo = Mbo +  Mbx
        i =  i  +  1

      if(i.eq.50000*int(i/50000)) then
        print*,'i= ',i,'; Log10(Radio)= ',Log10(Radio),'; P= ',Po,
     1           '; Masa= ',Mso
        print*, '-g_tt =  ', no, ';   g_rr =  ', mo
        print*, 'g_tt*g_rr=  ', no*mo       !*.299151515d0
        print*, 'no_central =  ', 1.d0/no
        print*, 'Escalar de curvatura:  R =  ', Ro
        print*, 'denominador =  ', 2.d0*f1o+xo*R1o*f2o,'  R1 =  ', R1o
        print*, 'R1²f2²/f1 =  ', R1o**2.d0*f2o**2.d0/f1o
        print*, 'f/f2 =  ', fo/f2o,'    f1R/f2 =   ', f1o*Ro/f2o
        print*, 'f3R²/f2 =  ', f3o*Ro**2.d0/f2o
        print*, 'Error de R =  ',error_R
        print*, 'Radio =  ', xo
        print*, '----------------------------------------------------'
      endif

      Enddo
       no_central=1.d0/no
      END

and I’m trying to write it out in Python.

First of all, I’m not sure what the index “i” is doing because it’s never mentioned before. I assumed it was for some kind of “for” loop. is it for the “if” statement? I kind of understand that the first time it’s mentioned in the code it means that it’ll increment by “1”. But aside from that, I have no idea what it does in this part of the code (the only part it’s mentioned in the entire program).

Second: in the line print*,'i= ',i,'; Log10(Radio)= ',Log10(Radio),'; P= ',Po,'; Masa= ',Mso I don’t understand if the semicolon indicates some kind of “new line” when it’s printed. Does anyone know what it does?

I tried looking for a solution online, but couldn’t find one. I understand that it might not be something difficult (for someone who uses Fortran); but I’m unfamiliar with Fortran.