I am trying to call a LE C program (test program that just prints the arguments) from my COBOL program.
I pass a structure to my C program and print the received values. However, as you can see in the output, the first 2 bytes of function are missing when printing argv[1]. Could anyone help fix this?
Is this the correct way to call a LE C program from COBOL program (I need to pass upto 3 structures like CALL cpgm USING struct1 struct2 struct3) or is there a better way? Any examples would really help.

COBOL program:

IDENTIFICATION DIVISION.                    
PROGRAM-ID. COBPGM.                         
DATA DIVISION.                              
WORKING-STORAGE SECTION.                    
01  EXPARM.                                 
    05  FUNKTION       PIC X(4) VALUE SPACES
    05  FUNC REDEFINES FUNKTION.            
        10 FILLER      PIC X(03).           
        10 FUNC-SUFFIX PIC X.               
    05  STAT           PIC X(2) VALUE SPACES
    05  ID-CODE   PIC S9(4) COMP.      
    05  ID-NAME   PIC X(08).           
PROCEDURE DIVISION.                         
    MOVE 'FUNC' TO FUNKTION.                
    MOVE '1' TO FUNC-SUFFIX.                
    MOVE 'OK' TO STAT.                      
    MOVE 1234 TO ID-CODE.              
    MOVE 'IDNAME ' TO ID-NAME.        
                                                
    CALL 'CPGM' USING EXPARM.               
    STOP RUN.

C program:

#include <stdio.h>                 
#include <stdlib.h>                
#include <string.h>                
#include <errno.h>                 
#include <limits.h>                
typedef struct EXPARM1{            
char FUNCTION[4];                  
char STATUS[3];                    
int ID_CODE;                  
char ID_NAME[9];              
}EXPARM;                           
                               
int main(int argc, char **argv) {  
printf("argc : %dn",argc);        
if (argc>=1) {                     
    printf("argv[0] : %sn",argv[0]);
    printf("argv[1] : %sn",argv[1]);
}                                  
return 0;                          
}

Output:
argc : 2
argv.0. : COBPGM
argv.1. : N1OK.KIDNAME ENDMBLK-.s..

the above ‘.K’ in the output is 1234 in HEX and not sure where ENDMBLK is coming from.

Tried to run the program and it printed the above output which I can’t make sense of.