#include <iostream>

int main()
{
    // char array
    char name1[] = "Hello";
    std::cout << "name1 = " << name1 << std::endl;
    std::cout << "&name1 = " << &name1 << std::endl;
    std::cout << "*name1 = " << *name1 << std::endl;
    std::cout << "name1[0] = " << name1[0] << std::endl;
    std::cout << "&name1[0] = " << &name1[0] << std::endl << std::endl;
    // char 
    const char* name2 {"World"};
    std::cout << "name2 = " << name2 << std::endl;
    std::cout << "&name2 = " << &name2 << std::endl;
    std::cout << "*name2 = " << *name2 << std::endl;
    std::cout << "name2[0] = " << name2[0] << std::endl;
    std::cout << "&name2[0] = " << &name2[0] << std::endl;



}

Both ways of implementing – char array and char pointer gives same result.

1. Are array of characters stored into array of pointers pointing to each character in the array?
2. Why does name1 return Hello, in case of int, it returns address.
3. name1[0] return H but why does &name1[0] return Hello ? Should it not return address of ‘H’ if ‘H’ is stored in separate memory location?
4. What is the difference in the two ways of implementing?
5. Why do we need to have mandatory ‘const’ before char* ( C++20 compiler error on Visual Studio if const is not used)

Tried the two ways and confused why do they return the same result and different from array of int or pointer to int.

name1 = Hello
&name1 = 00000078C1FEFBA4
*name1 = H
name1[0] = H
&name1[0] = Hello

name2 = World
&name2 = 00000078C1FEFBC8
*name2 = W
name2[0] = W
&name2[0] = World