as far as I know integers for example are placed in memory at integer multiples of their size. Can I access a set of bytes starting at non-integer multiple of sizeof(int) via a pointer as an int? The code below seems to work, producing

Size of int: 4
native byte order: LSB
0 127 0 0 0 0 0 0 0 0 0 0

Is it guaranteed, or not? Thanks.

#include <string.h>
#include <iostream>
#include <bit>
using namespace std;

int main()
{
    cerr<<"Size of int: "<<sizeof(int)<<endl;
    if(std::endian::native == std::endian::little) cerr<<"native byte order: LSB"<<endl;
    else cerr<<"native byte order: MSB"<<endl;

    const int N = 3;
    int array_int[N];
    memset(array_int,0,sizeof(int)*N);
    std::byte *array_byte = (std::byte*)array_int;

    int *ptr = (int*)(array_byte+1);
    *ptr = 127;

    for(int i=0; i<N*sizeof(int); ++i) cerr<<(int)(array_byte[i])<<"  ";
    cerr<<endl;

    return 0;
}

The above example compiles and runs as expected naively