I have a simple code at down:

int global1(int x)
{
 return x * 5;
}

int global2(int x)
{
 return x + 5;
}

struct some_struct {
  int a;

  int foo1(int x)
  {
     return x * a;
  }

  int foo2(int x)
  {
     return x + a;
  }

  int bar1(int x, bool a)
  {
     auto func = a ? global1 : global2; // works
     // auto func = a ? &global1 : &global2; // also works

     return func(x);
  }

  int problem_function(int x, bool a) // It is my question
  {
     auto func = a ? foo1 : foo2; // gives error
     // auto func = a ? &foo1 : &foo2; // also gives error
     // auto func = a ? &this->foo1 : &this->foo2; // also gives error

     return func(x);
  }
};

It is very simplyfied form of the code in the real code i have no way to carry function on outside like how i did in this with global1() & global2()

I wanna call one of functions in the struct but using a pointer to a function but it gives error.

Note: I cant use if else becouse in the real code its not returns func(x) in real code i use func(x) as a condition for a function in a loop (I am not joking its literaly what i said)

A part from real code:

void* find_first(ExprToken* (*cond)(bool (*)(ExprToken*))) {...} // yeah

I know if I want to call a function of struct I have to tell which variable(struct) I am using to compiler but how.

Is even C++ supports function pointer in struct?