If 1111..n times is a binary number then what is its decimal number please also tell the process
I am getting 12^n-1+12^n-2+…1*2^0.
| Column A | Column B |
|---|---|
| Cell 1 | Cell 2 |
| Cell 3 | Cell 4 |
| Column A | Column B |
| ——– | ——- |
| Cell 1 | Cell 2 |
| Cell 3 | Cell 4 |
| Column A | Column B |
| ——– | ——– |
| Cell 1 | Cell 2 |
| Cell 3 | Cell 4 |
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