When I run the below program, I do not understand why buf.data, is empty. At first I thought It may be my misunderstanding of memory, so I tried to malloc the buffer array, but it didnt change, the programs output.

#include <stdio.h>

typedef void Write(void *, char);

struct Writer {
  void *impl;
  Write *write;
};

void fprint(struct Writer *w, const char *s) {
  while (*s)
    w->write(w->impl, *s++);
}

struct StandardOut {};

void StandardOut_write(struct StandardOut *w, char c) { fputc(c, stdout); }

struct Buffer {
  char *data;
  size_t size;
};

void Buffer_write(struct Buffer *b, char c) {
  if (b->size > 0) {
    *b->data++ = c;
    b->size--;
  }
}

int main() {
  struct Writer stdoutw = (struct Writer){
      .impl = &(struct StandardOut){},
      .write = (Write *)StandardOut_write,
  };

  fprint(&stdoutw, "console meatn");

  char data[1024];

  struct Writer bufw = (struct Writer){
      .impl = &(struct Buffer){.data = data, .size = sizeof(data)},
      .write = (Write *)Buffer_write,
  };

  fprint(&bufw, "buffered beefalon");

  struct Buffer buf = *(struct Buffer *)bufw.impl;
  fprint(&stdoutw, buf.data);

  fprint(&stdoutw, data[0] ? data : "buffer is empty");
}

This is the output of the program:

❯ zig cc interfaces.c
❯ ./a.out
console meat
buffered beefalo

So it is not printing the message in the buffer. Further the array is not empty from mains point of view. Because otherwise the ternary message should be printed, and we would not see the buffered message at all.

I dont know any c, so I dont know if this code is good or bad practice. Just messing around.