You can use the parse_qs() method to parse queries:

from bs4 import BeautifulSoup
from urllib.parse import urlparse, parse_qs

html_content = '''
<td>
    <a href="/?p=section&a=details&id=37627">Some Text Here</a>
</td>
'''

# Parse the HTML content
soup = BeautifulSoup(html_content, 'html.parser')

# Find the <a> tag
a_tag = soup.find('a')

# Extract the href attribute
href = a_tag.get('href')

# Parse the URL to get the query parameters
parsed_url = urlparse(href)
# for py2: parsed_url = urlparse.urlparse(url)
query_params = parse_qs(parsed_url.query)

# Get the 'id' parameter
id_value = query_params.get('id', [None])[0]

print(id_value)  # Output: 37627

There are two way to make this. You can simply cut the string from ‘id=’ to the next occurence of double quote character or ‘&’ if it is possible that the link can have more query params or just use the regex. I would prefer to use the regex, as it is more simple and accurate.

FIRST SOLUTION:(Cut the string)

# check that the string contains the part 'id='
id_start = (soup.td.a).find('id=')
if id_start != -1:
    # id_start contains the index of 'id=', to get the actual index of the id we need to add 3 to this value
    id_start += len('id=')
    # we find the occurence of '"' starting from 'id=' index, if not found search for '&'
    id_end = (soup.td.a).find('"', id_start)
    if(id_end == -1):
         id_end = (soup.td.a).find('&', id_start)
    id_value = (soup.td.a)[id_start:id_end]

SECOND SOLUTION:

import re
# Regular expression to find the 'id' parameter
regex= r'id=(d+)'
# Search for the pattern in the string
match = re.search(regex, soup.td.a)
if match:
    id_value = match.group(1)

Hope it works!!