Is there a way to remove an item from the first list (versions) if no item meeting the condition is found.
here’s the condition:
s -> s.getId().equals(identifier) && s.getStatus().equals("CANCELLED").
here’s the iteration:
versions.stream()
.flatMap(v -> v.getDetails().stream())
.flatMap(m -> m.getStatuses().stream())
.filter(s -> s.getId().equals(identifier) && s.getStatus().equals("CANCELLED"))
4
If you want to remove from versions any instance whose all innermost elements do not match a certain condition (id equals to identifier and status equals to CANCELLED), then you could:
- Employ a single
filteron yourversionslist. - Stream the
detailsof eachversion. flatMapthe details’ status to have all the status corresponded to a singleversion.- Finally, since we’ve used
filter, negate the logic to keep (not remove) everyversionthat contains at least one object (not none) withidequals toidentifierandstatusequals toCANCELLED.
versions.stream()
.filter(v -> v.getDetails().stream()
.flatMap(d -> d.getStatus().stream())
.anyMatch(s -> s.getId().equals(identifier) && s.getStatus().equals("CANCELLED"))
)
.collect(Collectors.toList());
Here is a demo at OneCompiler.