I have a scenario where i stuck not getting how do i need to implement.

I have string need to find count of each letter -> ('a',2). Sort by second value which is count and order by first if same count for other letter as well.

My code :

s = 'aabbbccde'
c = re.finditer(r'([w])(1*)',s)
lst = []

for i in c:
    lst.append((list(map(str,set(i.__getitem__(0))))[0] , len(i.__getitem__(0))))
    
var = sorted(
lst,
key=lambda x: x[1],reverse=True)

for i in sorted( (sorted(var,key=lambda x:x[1],reverse=True)) , key=lambda x:x[0])[:3]:
    print(i[0],i[1])

My output :

a 2
b 3
c 2

I am not getting as expected output :

b 3
a 2
c 2

Where i am going wrong in my code or is their any efficent way to do it …