I’m trying to use PowerShell and WPF to write a Datagrid with an image column. But I can’t get the image to display for the life of me.
I need to display an image “in memory” as opposed to a physical image on disk. Hence i try and convert it in this example:
Add-Type -AssemblyName PresentationCore, PresentationFramework, WindowsBase
# Function to convert image file to BitmapSource
function Convert-ImageFileToBitmapSource {
param (
[string] $ImagePath
)
# Load the image from file
$bitmap = New-Object System.Drawing.Bitmap($ImagePath)
# Convert Bitmap to BitmapSource
$bitmapStream = New-Object System.IO.MemoryStream
$bitmap.Save($bitmapStream, [System.Drawing.Imaging.ImageFormat]::Png)
$bitmapSource = New-Object System.Windows.Media.Imaging.BitmapImage
$bitmapSource.BeginInit()
$bitmapSource.StreamSource = $bitmapStream
$bitmapSource.EndInit()
# Dispose of the original Bitmap to free resources
$bitmap.Dispose()
return $bitmapSource
}
# Create a DataTable with columns
$dataTable = New-Object System.Data.DataTable
$dataTable.Columns.Add("Name", [System.String])
$dataTable.Columns.Add("Icon", [System.Windows.Media.Imaging.BitmapSource])
# Load image from file and add to DataTable
$imagePath = "C:ExampleIcon.png"
$iconBitmapSource = Convert-ImageFileToBitmapSource -ImagePath $imagePath
# Add rows to DataTable
$row1 = $dataTable.NewRow()
$row1["Name"] = "Icon"
$row1["Icon"] = $iconBitmapSource
$dataTable.Rows.Add($row1)
# Create WPF XAML content
[xml]$xaml = @"
<Window xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="Image in DataGrid Example" Height="400" Width="600">
<Grid>
<DataGrid Name="myGrid" AutoGenerateColumns="False" ItemsSource="{Binding}">
<DataGrid.Columns>
<DataGridTextColumn Header="Name" Binding="{Binding Name}" Width="*"/>
<DataGridTemplateColumn Header="Icon">
<DataGridTemplateColumn.CellTemplate>
<DataTemplate>
<Image Source="{Binding Icon}" Width="32" Height="32" />
</DataTemplate>
</DataGridTemplateColumn.CellTemplate>
</DataGridTemplateColumn>
</DataGrid.Columns>
</DataGrid>
</Grid>
</Window>
"@
# Load XAML content
$reader = (New-Object System.Xml.XmlNodeReader $xaml)
$window = [Windows.Markup.XamlReader]::Load($reader)
# Set DataContext to DataTable
$window.DataContext = $dataTable.DefaultView
# Show the window
$window.ShowDialog() | Out-Null